#include <reg52.h>
#define uint unsigned int
#define uchar unsigned char
sbit out10=P1^0;//  CE =1
sbit out11=P1^1;//  R/C
sbit out12=P1^2;//  ad out =1
sbit out13=P1^3;//  cs  =0
sbit out14=P1^4;//  ad out =0
sbit out15=P1^5;//  ad 信号  =0转换结束
sbit out16=P1^6;//  合格信号
sbit out17=P1^7;//  超信号
sbit out24=P2^4;//  低信号
sbit out25=P2^5;//  工作命令
const float code ad2vh[]={0,0.320,0.640,0.960,1.280,1.600,1.920,2.240,2.560,2.880,
3.200,3.520,3.840,4.160,4.480,4.800};//高8位字节
const float code ad2vl[]={0,0.020,0.040,0.060,0.080,0.100,0.120,0.140,0.160,0.180,
0.200,0.220,0.240,0.260,0.280,0.300};//底8位字节
//**********数值*******
int a;
int b;
int n;
//********初始化*********//
void restart()      
{
    out13=0x1;
    out10=0x0;//AD关闭
    out12=0x1;
    out14=0x0;//AD8位设置
    out15=0x0;
    out16=0x0;
    out17=0x0;
    out24=0x0;    
}

//***********AD输入***************//
void adin()
{
    a=P3;//底8位存入a
    b=P2;//高8位存入b
    b=b&0xf0;
    n=a+b;//AD数据存入N
    n=ad2vh[n&0xf0]+ad2vl[n&0xf0];//ad数据转换为10进制
}


//********************主程序************    
void main()
{
    while(1)
    {
        while(out25==1)
        {
            restart;
            out13=0x0;
            out10=0x1;//启动AD
            while(out15==0)//等待转换
            {
                adin;
                if(a<11&&a>9)
                {
                    out16=0x1;    
                }
                if(a<9)
                {
                    out24=1;
                }
                if(a>11)
                {
                    out17=0x1;
                }
                
            }
        }
    }
    
}

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用的是AD574，帮忙看下程序有没有错误，编译时有三个警告···
11脚的-15v可以用开关电源上的-15v直接接上么?第十脚的基准电压输入要输几V???